SOLUTION: 2.) Jill has $2.30 in dimes and quarters. The number of dimes is 5 less than the number of quarters. How many coins of each?

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Question 710240: 2.) Jill has $2.30 in dimes and quarters. The number of dimes is 5 less than the number of quarters. How many coins of each?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Jill has $2.30 in dimes and quarters. The number of dimes is 5 less than the number of quarters. How many coins of each?
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Quantity Eq:: d = q - 5
Value Eq::::: 10d + 25q = 230 cents
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Substitute for "d" and solve for "q":
10(q-5) + 25q = 230
10q - 50 + 25q = 230
35q = 280
q = 8 (# of quarters)
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Solve for "d":
d = q-5
d = 3 (# of dimes)
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Cheers,
Stan H.
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