A group consists of 15 people: 5 Americans, 6 Canadians and 4 Mexicans.
(a) In how many ways can a sub-group of 4 people be selected?
(5+6+4 people CHOOSE 4) = (15 people CHOOSE 4) = C(15,4) = 1365 ways.
(b) In how many ways can a sub-group of 4 people consist of all Canadians?
(6 Canadians CHOOSE 4) = C(6,4) = 15 ways
(c) In how many ways can a sub-group of 4 people consist of 2 Canadians and 2
Mexicans?
(6 Canadians CHOOSE 2) times (4 Mexicans CHOOSE 2) = C(6,2)·C(4,2) = 15·6 = 90 ways
Edwin