SOLUTION: please help me solve this: if the perimeter of square A is half the perimeter of aquare B, then the area of aquare B is how many times the area of aquare A? thank you for your ti

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Question 710129: please help me solve this:
if the perimeter of square A is half the perimeter of aquare B, then the area of aquare B is how many times the area of aquare A?
thank you for your time!
Found 2 solutions by josmiceli, solver91311:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I'll say that the perimeter of the smaller square is
+4s+ and the perimeter of the larger square is +8s+
That means a side of the smaller square is +4s%2F4+=+s+
and a side of the larger square is +8s%2F4+=+2s+
Area of larger square = +%282s%29%5E2+=+4s%5E2+
Area of smaller square = +s%5E2+
( area B ) / ( area A ) = +4s%5E2+%2F+s%5E2+=+4+%2F+1+
Area B is 4 times area A

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The perimeter of a square with side measure is . The area of such a square is .

A square with one-half the perimeter would have a perimeter of , hence the measure of one side would be . And the area of this smaller square is .



Solve for

John

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