Question 710073: Find three consecutive even integers such that the sum of three times the first, and twice the third is twenty less than six times the second.
Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! let the 3 consecutive nos are x-1 ,x , x+1
the sum of three times the first, and twice the third is twenty less than six times the second.
so 3(x-1)+2(x+1)=6x-20
or 3x-3+2x+2=6x-20
or 5x-1=6x-20
or x=20-1=19
so the nos are 18,19,20
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