SOLUTION: In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, then the dividend is

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, then the dividend is      Log On


   

Question 709986: In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, then the dividend is
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The website system is cutting out part of my solution - I may try adding it again if found missing...
Use variables assigned this way:
Q=quotient, N=dividend, D=divisor, r=remainder without the denominator.

Q=%28N%2FD%29%2B%28r%2FD%29 and unfortunately not showing, highlight%28N=D%2AQ-%28r%2FD%29%29

Facts given mean D=10*Q, D=5*r, r=46.

Some steps to solving:
D=5*46, D=230.
Also D=10*Q so Q=D/10, and knowing D, Q=230/10, Q=23

Summary of what found so far:
D=230, Q=23,
Substitute the values.
N=230%2A23-%2846%2F230%29, highlight%28N=5290-%2823%2F115%29%29