SOLUTION: Two cyclist start 10 kilometers apart. They are traveling towards each other, cyclist A traveling at an average of 3.0m/s and cyclist B at a speed of 5.0 m/s. Where will the cyclis
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Question 709690: Two cyclist start 10 kilometers apart. They are traveling towards each other, cyclist A traveling at an average of 3.0m/s and cyclist B at a speed of 5.0 m/s. Where will the cyclists meet? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Two cyclist start 10 kilometers apart. They are traveling towards each other, cyclist A traveling at an average of 3.0m/s and cyclist B at a speed of 5.0 m/s. Where will the cyclists meet?
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Convert kilometers to meters:
10 kilometers = 10*1000 = 10000
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Determine the time (t) when they will meet (applying the distance formula):
d = rt
3t + 5t = 10000
8t = 10000
t = 1250 secs (this is "When" the cyclist will meet)
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this is "Where" the cyclist will meet:
3*1250 = 3750 m or 3.75 kilometers (distance traveled by 3m/s cyclist)
5*1250 = 6250 m or 6.25 kilometers (distance traveled by 5m/s cyclist)
