SOLUTION: f(x)= 3x/1+x, x≥0 A) Find the range b)For which values is f(x)=2 I know the answer to A in my book is [0,3) Is the x value 0, because the problem state x is greater tha

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: f(x)= 3x/1+x, x≥0 A) Find the range b)For which values is f(x)=2 I know the answer to A in my book is [0,3) Is the x value 0, because the problem state x is greater tha      Log On


   

Question 709617: f(x)= 3x/1+x, x≥0
A) Find the range
b)For which values is f(x)=2
I know the answer to A in my book is [0,3)
Is the x value 0, because the problem state x is greater than or equal to 0?
I don't under stand why the y value is 3 and how to find the range.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)= 3x/1+x, x≥0
-----------------------
A) Find the range
The horizontal asymptote is y = 3.
Since the domain is x>=0, range is {0,3)
---------------------------------------------------
b)For which values is f(x)=2
Solve (3x)/(1+x) = 2
3x = 2+2x
x = 2
------------------------------------------------
Graph, so you can see why range is [0,3)
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C%283x%29%2F%281%2Bx%29%29
==================
Cheers,
Stan H.