SOLUTION: in a triangle one side is twice as long as the shortest side and another is two inches less than four times the shortest side. if the perimeter is 33 inches, what are the side

Algebra ->  Triangles -> SOLUTION: in a triangle one side is twice as long as the shortest side and another is two inches less than four times the shortest side. if the perimeter is 33 inches, what are the side       Log On


   



Question 709496:
in a triangle one side is twice as long as the shortest side and another is two inches less than four times the shortest side. if the perimeter is 33 inches, what are the side lengths

Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
P=A+B+C
LET A BE THE SHORTEST SIDE.
LET B=2A
LET C=4A-2
P=A+2A+4A-2
33=7A-2
33+2=7A
35=7A 35/7=A
5=A ANS. FOR THE SHORTEST SIDE.
2*5=10 FOR THE NEXT SIDE.
4*5-2=20-2=18 FOR THE THIRD SIDE.
PROOF:
5+10+18=33
33=33