SOLUTION: State Range & Graph Function. f(x)= x^2, -1 ≤ x ≤ 0 I am confused as to how to graph that, I know what the graph of f(x)=x^2 looks like and I under stand that the line

Algebra ->  Rational-functions -> SOLUTION: State Range & Graph Function. f(x)= x^2, -1 ≤ x ≤ 0 I am confused as to how to graph that, I know what the graph of f(x)=x^2 looks like and I under stand that the line      Log On


   

Question 709490: State Range & Graph Function. f(x)= x^2, -1 ≤ x ≤ 0
I am confused as to how to graph that, I know what the graph of f(x)=x^2 looks like and I under stand that the line would start at 0 for x values and go to the left.
What is confusing me is my book shows the graph stopping at y=1 , and states the range is y ∈[0,1)
Can someone explain why it stops at y=1 and what it means to say that the range is y ∈[0,1).
Thanks
Answer by josgarithmetic(39627) About Me  (Show Source):
You can put this solution on YOUR website!
"Range" is what values the function is, what the set of function values is.

Your example was specified to use x only between -1 and 0, inclusive. If you SQUARE x, the result will be POSITIVE. The domain values were specified as mostly negative, but any real number squared is POSITIVE.

"what it means to say that the range is y ∈[0,1)",
The values for y are elements of the set of real numbers greater than or equal to zero, and less than 1. Again, those are positive values (except for maybe zero) because f(x)=x^2 is positive.