Question 70946: 3+|1-(x/2)|>=5
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! 3 + |1-(x/2)| >= 5
:
subtract 3 from both sides:
|1 - (x/2)| >= 5 - 3
|1 - (x/2)| >= 2
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Two situations when you remove the abs
one
1 - (x/2) >= 2
:
Subtract 1 from both sides:
-(x/2) >= 2 - 1
-(x/2) >= 1
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Multiply equation by 2 and you have:
-x >= 2
:
We want x to be positive, mult by -1, you must reverse the inequality sign
x <= -2
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Situation 2:
1 - (x/2) <= -2
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Subtract 1 from both sides:
-(x/2) <= -2 - 1
-(x/2) <= -3
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Multiply equation by 2 and you have:
-x <= -6
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We want x to be positive, mult by -1, you must reverse the inequality sign
x >= 6
:
:
Solutions x <= -2; x >= 6
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