SOLUTION: Two joggers, one averaging 7mph and one averaging 4mph, start from a disgnated initial point. The slower jogger arrives at the end of the run 40 minutes after the other jogger. Fin

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Question 709392: Two joggers, one averaging 7mph and one averaging 4mph, start from a disgnated initial point. The slower jogger arrives at the end of the run 40 minutes after the other jogger. Find the distance of the run.
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
pp
The Joggers__________rate__________time hrs.___________distance
fast_________________7_____________t___________________d
slower_______________4_____________t+2/3_______________d

The (2/3) of the hour is the same as 40 minutes.

The distance that each jogged is the same, so equate the expressions for their distance, rate in miles per hour multiplied by the hours.

7t=4%28t%2B2%2F3%29, and solve for t in hours. Once t is known, use either joggers data to compute d.


7t=4t%2B8%2F3
3t=8%2F3
highlight%28t=8%2F9%29, hours

highlight%28d=7%2A%288%2F9%29%29, miles

(This result appeared to be about a 10 kilometer event.)