SOLUTION: log base 5 * square root of 125 - log base 2 * square root of 2 = ?

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Question 709332: log base 5 * square root of 125 - log base 2 * square root of 2 = ?
Answer by hheuler(6) About Me  (Show Source):
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log base 5 * square root of 125 - log base 2 * square root of 2
= log_5 [sqrt(125)] - log_2[sqrt(2)]
= log_5[5^3]^(1/2) - log_2 [2]^(1/2)
= log_5 [5]^3/2 - log_2[2]^(1/2)
= 3/2 - 1/2
= 1
We are using the log property that log_a a^b = b.