SOLUTION: Write a polynomial division that has a quotient of x+3 and a remainder of 2.

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Question 709120: Write a polynomial division that has a quotient of x+3 and a remainder of 2.
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
You could make any divisor you want. The "2" remainder would be the numerator counting the denominations of that divisor. Pick something uncomplicated for your divisor, like a binomial, something (x+k) or (x-k), where k is preferably a rational number. Pick an actual value.

When you have a divisor, and you have your quotient with the remainder, you need a dividend. You find this dividend by MULTIPLYING your given quotient BY your chosen divisor.

Generally I am showing what I said:
Let's take x-k as a divisor. We have a result of division being %28x%2B3%29%2B2%2F%28x-k%29. That is not simply remainder=2. That is showing what exactly the remainder is counting.
What Next? Calculate this: %28x-k%29%28x%2B3%2B2%2F%28x-k%29%29. THAT represents your dividend.