SOLUTION: I have NO clue how to do this.... f(x) = sqrt(25-x^2) Can someone help me? Thanks Melissa

Algebra ->  Square-cubic-other-roots -> SOLUTION: I have NO clue how to do this.... f(x) = sqrt(25-x^2) Can someone help me? Thanks Melissa      Log On


   



Question 709085: I have NO clue how to do this....
f(x) = sqrt(25-x^2)
Can someone help me?
Thanks
Melissa

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29+=+sqrt%2825-x%5E2%29

f%28x%29+=+sqrt%285%5E2-x%5E2%29

f%28x%29+=+sqrt%28%285-x%29%285%2Bx%29%29

f%28x%29+=+sqrt%285-x%29sqrt%285%2Bx%29

set f%28x%29+=0 to find roots

+sqrt%285-x%29sqrt%285%2Bx%29=0

if +sqrt%285-x%29=0...=>...+5-x=0 .=>...+5=x

if +sqrt%285%2Bx%29=0...=>...+5%2Bx=0 .=>...+-5=x

domain:

range: