SOLUTION: A coin bank contains nickels, dimes, and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coins are in the
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-> SOLUTION: A coin bank contains nickels, dimes, and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coins are in the
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Question 70905: A coin bank contains nickels, dimes, and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coins are in the bank? Answer by mathmaven53(29) (Show Source):
You can put this solution on YOUR website! Let number of nickels be N
number of dimes be D
number of quarters be Q
By the conditions of the problem
D= 2Q
Q = N + 11
The value of the coins is .05N + .1D + .25Q = 5.45
We have N = Q - 11
Substitute into equation for value of coins
.05(Q - 11) + .2Q + .25Q = 5.45
Solving for Q gives Q = 12
Then N = Q - 11
= 1
D = 2Q
= 24
1 nickel, 24 dimes , 12 quarters
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