Question 708948: how do i solve the system h=-6g-4 h=-2g+28 using substitutions?
Answer by malnessa(2)   (Show Source):
You can put this solution on YOUR website! Since it is substitution, then you can let just set the two equations equal to themselves. This will help you to solve for g.
h=-6g-4 h=-2g+28
-6g-4=-2g+28 Add 2g to both sides
-4g-4=28 Add 4 to both sides
-4g =32 Divide both sides by -4
g =-8
Now use what you solved for g to solve for h. It does not matter which equation you use.
h=-6g-4 Substitute -8 for g
h=-6(-8)-4
h=48-4
h=44
So now you have your value for h and g. In other words your answer is (-8,44).
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