Question 70888: I have two problems: One is How do I get thex,y points for the problem y=x^5
I used the graphing calculator and got the graph but I need to list x,y points.
Next I need to solve x^2-12x=-36
Would I move the -36 to the left and have x^2-12x+36=0?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I have two problems: One is How do I get thex,y points for the problem y=x^5
I used the graphing calculator and got the graph but I need to list x,y points.
y=x^5 is the rule you follow. You can put any number in for "x".
For example:
If x=1, y=1^5=5 giving you the point (1,5)
If x=2, y=2^5=25, giving you the point (2,25)
etc.
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Next I need to solve x^2-12x=-36
Would I move the -36 to the left and have x^2-12x+36=0?
That's the way to start.
Then factor to get (x-6)^2=0
So x-6=0
x=6
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Cheers,
Stan H.
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