SOLUTION: y^3+8y^2-y-8

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Question 708860: y^3+8y^2-y-8
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y%5E3%2B8y%5E2-y-8 Start with the given expression


%28y%5E3%2B8y%5E2%29%2B%28-y-8%29 Group the terms in two pairs


y%5E2%28y%2B8%29-1%28y%2B8%29 Factor out the GCF y%5E2 out of the first group. Factor out the GCF -1 out of the second group


%28y%5E2-1%29%28y%2B8%29 Since we have the common term y%2B8, we can combine like terms


%28y-1%29%28y%2B1%29%28y%2B8%29 Factor y%5E2-1 to get %28y-1%29%28y%2B1%29 using the difference of squares rule


So y%5E3%2B8y%5E2-y-8 factors to %28y-1%29%28y%2B1%29%28y%2B8%29


In other words, y%5E3%2B8y%5E2-y-8=%28y-1%29%28y%2B1%29%28y%2B8%29 for all values of y