SOLUTION: Factor Completely. y^3-12y^2+36y I am trying to figure this problem out and I came with y(y^2-12y+36) I wanted to check to make sure this was right before moving on. Thanks

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Factor Completely. y^3-12y^2+36y I am trying to figure this problem out and I came with y(y^2-12y+36) I wanted to check to make sure this was right before moving on. Thanks      Log On


   

Question 70840This question is from textbook Beginning Algebra
: Factor Completely. y^3-12y^2+36y
I am trying to figure this problem out and I came with y(y^2-12y+36)
I wanted to check to make sure this was right before moving on. Thanks This question is from textbook Beginning Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Well you're almost there, you have the first step down. Next you need to factor the terms inside the parenthesis. First we need to find out what terms multiply to 36 and add to -12: -6 and -6 works perfectly. These are going to be the terms in our factors So we can further factor it to:
y%28y%5E2-12y%2B36%29
y%28y-6%29%28y-6%29Notice the -6's? If you FOIL this you get y^2-12y+36
And it could be further written as
y%28y-6%29%5E2Since there are two (y-6) terms