SOLUTION: graph the circle x^2+ y^2-6x+4y-3=0

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Question 708177: graph the circle x^2+ y^2-6x+4y-3=0
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square for both variables and convert the equation to standard form; from this you can read the point (h,k) for center of the circle, and read the radius value.

Given: x^2+ y^2-6x+4y-3=0
%28x%5E2-6x%29%2B%28y%5E2%2B4y%29-3=0
The missing square for the x part is (6/2)^2=3^2=9
The missing square for the y part is (4/2)^2=4

%28x%5E2-6x%2B9%29%2B%28y%5E2%2B4y%2B4%29-3-9-4=0
%28x-3%29%5E2%2B%28y%2B2%29%5E2-16=0
%28x-3%29%5E2%2B%28y%2B2%29%5E2=16
highlight%28%28x-3%29%5E2%2B%28y%2B2%29%5E2=4%5E2%29

The center is at (3,-2) and radius is 4 units.