You can put this solution on YOUR website! If you were to solve the equality for t, you would come to a critical point at x=7/4. If the denominator is examined for equality to 0, you find a critical point at x=1/2.
5/(2t-1)=2
5=2(2t-1)
5=4t-2
t=7/4
Check the truth or falseness of the given inequality for the intervals,
(-infinity,(1/2)), ((1/2),7/4), [(7/4),+infinity).
Picking any value for t in each interval,
I found First one is good; second one fails; third one is good.