SOLUTION: find three consecutive even integers such that fives times the middle integer is twelve more then twice the sum of the first and third.

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Question 708120: find three consecutive even integers such that fives times the middle integer is twelve more then twice the sum of the first and third.
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
n is an integer.


fives times the middle integer is:
5(2n+2)=

twelve more then twice the sum of the first and third.:
12+2(2n+2n+4)

Putting it together:
5(2n+2)=12+2(2n+2n+4)
10n+10=12+8n+8
10n+10=8n+20
2n+10=20
2n=10, n=5.

The numbers are 10, 12, 14.