SOLUTION: My question is too find y: (6/p)-ax=(m/y)+k I'm not sure where to start and need a bit of help to figure out where to go with this problem.
Thank you for the help
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-> SOLUTION: My question is too find y: (6/p)-ax=(m/y)+k I'm not sure where to start and need a bit of help to figure out where to go with this problem.
Thank you for the help
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Question 708042: My question is too find y: (6/p)-ax=(m/y)+k I'm not sure where to start and need a bit of help to figure out where to go with this problem.
Thank you for the help
You can put this solution on YOUR website! Think about undoing everything that was done to y. Work from the outside inward.
(1)
Add -k to both sides.
(2)
Multiply both sides by (1/m).
See now you have some expression equals (1/y), so you really want the reciprocal of this.
(3)
Invert left and right sides and simplify the left-hand expression.
Using symmetric property of equality, we want to manage .
Skipping the step, you should find .
Here's a different way that doesn't solve for the reciprocal.
Multiply through by LCD
6·y - p·y·a·x = p·m + p·y·k
Get all the terms in y on the left and the term
that does not contain y on the other side:
6·y - p·y·a·x - p·y·k = p·m
Factor out y on the left:
y·(6- p·a·x-p·k) = p·m
Divide both sides by (6-p·a·x-p·k)
Edwin
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