SOLUTION: What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the largest
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Question 708009
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What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the largest
Answer by
CubeyThePenguin(3113)
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consecutive integers: (x-1), x, (x+1)
(x-1)(x) = 5(x+1) - 5
x^2 - x = 5x
x^2 - 6x = 0
x(x - 6) = 0
x = 0, x = 6
x is positive ---> integers: 5, 6, 7
