SOLUTION: Simplify. (m^4)^3(m^2)^9/(m^3)^2 I came up with two answers for this problem and not sure which one is the correct one and need some help. The first one I came up with is m^1

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Simplify. (m^4)^3(m^2)^9/(m^3)^2 I came up with two answers for this problem and not sure which one is the correct one and need some help. The first one I came up with is m^1      Log On


   



Question 70799This question is from textbook Beginning Algebra
: Simplify. (m^4)^3(m^2)^9/(m^3)^2
I came up with two answers for this problem and not sure which one is the correct one and need some help.
The first one I came up with is m^11
the second one is m^27
Thanks.
This question is from textbook Beginning Algebra

Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28m%5E4%29%5E3%28m%5E2%29%5E9%2F%28m%5E3%29%5E2Can be written as:
%28m%5E%284%2A3%29%29%28m%5E%282%2A9%29%29%2F%28m%5E%283%2A2%29%29Since a%5E%28x%29%5Ey=a%5E%28x%2Ay%29
%28m%5E12%2Am%5E18%29%2Fm%5E6Now you can divide
%28m%5E12%2Am%5Ecross%2818%29%29%2Fm%5Ecross%286%29To divide, subtract the exponents
%28m%5E12%2Am%5E12%29To multiply, add the exponents
%28m%5E24%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify. (m^4)^3(m^2)^9/(m^3)^2
= [(m^12)(m^18)/(m^6)
=(m^20)/(m^6)
=m^14
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Cheers,
Stan H.