SOLUTION: identify the root to the nearest tenth. y=4-x^2 i came out with x=-2.1 and x=1.9, but i am not sure if this is correct.

Algebra ->  Square-cubic-other-roots -> SOLUTION: identify the root to the nearest tenth. y=4-x^2 i came out with x=-2.1 and x=1.9, but i am not sure if this is correct.       Log On


   

Question 7078: identify the root to the nearest tenth.
y=4-x^2
i came out with x=-2.1 and x=1.9, but i am not sure if this is correct.
Answer by glabow(165) About Me  (Show Source):
You can put this solution on YOUR website!
It is unclear what you are asking here.
If you mean to find what x makes y=0, which is the usual requirement for such equations (and referred to as zeroes of the equation) then,
y+=+4+-+x%5E2+=+0 is easily seen to be x+=+%2B+2 and x+=+-2.