SOLUTION: Find all real numbers solutions for x and y (x and y can be negative). 2^2x - 3^2y = 15

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Question 70778: Find all real numbers solutions for x and y (x and y can be negative).
2^2x - 3^2y = 15
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2^2x - 3^2y = 15
4x-9y = 15
y=(4/9)x-(15/9)
Put in any value for x and solve for y.
Cheers,
Stan H.