Question 707769: I need to know how to solve f(x)=x^2cos2x and to determine whether the function is even, odd, or neither.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! I need to know how to solve f(x)=x^2cos2x and to determine whether the function is even, odd, or neither.
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Function is even if f(-x)=f(x)
Function is odd if f(-x)=-f(x)
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f(x)=x^2cos2x
cos(-2x)=cos2x (cos is an even function)
f(-x)=(-x)^2cos(-2x)=x^2cos2x=f)x)
Therefore, f(x) is an even function.
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To solve such equations, x must be determined and expressed in radians,
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