SOLUTION: how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 80% antifreeze

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Question 707743: how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 80% antifreeze
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 80% antifreeze
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Equation:
anti + anti = anti
0.30*60 + 0.90x = 0.80(60+x)
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30*60 + 90x = 80*60 + 80x
10x = 50*60
x = 300 gallons (amt. of 90% solution needed)
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Cheers,
Stan H.
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