SOLUTION: Admission to an amusement park is 8 dollars for adults and 5 dollars for children.if 201 was paid for 33 tickets, how many of each were purchased
Question 707704: Admission to an amusement park is 8 dollars for adults and 5 dollars for children.if 201 was paid for 33 tickets, how many of each were purchased Found 2 solutions by nerdybill, Stitch:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Admission to an amusement park is 8 dollars for adults and 5 dollars for children.if 201 was paid for 33 tickets, how many of each were purchased
.
Let x = number of adult tickets
then
33-x = number of children tickets
.
8x + 5(33-x) = 201
8x + 165-5x = 201
3x + 165 = 201
3x = 36
x = 12 (adult tickets)
.
Children's tickets:
33-x = 33-12 = 21
You can put this solution on YOUR website! Let A = number of adult tickets
Let C = number of child tickets
Equation 1:
Equation 2:
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Solve equation 2 for one of the variables.
Equation 2:
Plug (33-C) into equation 1 for A
Equation 1:
Multiply the 8 through.
Combine like terms.
Subtract 264 from both sides.
Divide both sides by -3.
Now solve for A, using 21 for C
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