Question 707458: #1 If y varies jointly as x and z, and inversely as u, and if y=6 when x=2,z=3, and u=4, what is the value of y when x=4, z=3 and u=8?
#2 Y varies indirectly as x. If y=3 when x=square root of 2, find y when x=square root of 6.
Thank you for your help.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! #1 If y varies jointly as x and z, and inversely as u, and if y=6 when x=2,z=3, and u=4, what is the value of y when x=4, z=3 and u=8?
-------
y = k(x*z)/u
---
Solve for "k" using "y=6 when x=2,z=3, and u=4":
6 = k(2*3)/4
k = 4
--------
Equation:
y = 4(x*z)/u
-----------------------
what is the value of y when x=4, z=3 and u=8?
y = 4(4*3/8)
y = 6
============================
#2 Y varies indirectly as x. If y=3 when x=square root of 2, find y when x=square root of 6.
-----------------------------
y = k/x
----
Solve for "k" using "y = 3 when x = sqrt(2):
3 = k/sqrt(2)
k = 3sqrt(2)
------
Equation:
y = (3sqrt(2))/x
-----
find y when x=square root of 6.
y = (3sqrt(2))/sqrt(6)
---
y = 3sqrt(1/3)
----------------------
Cheers,
Stan H.
===================
|
|
|
