Question 70717: #1) (2x-3) (4x+5)=0
#2) X to the second power -3x=0
How do I solve this?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! #1) (2x-3) (4x+5)=0
If this product is zero, one of those factors must be zero.
If 2x-3 =0, then x=3/2
If 4x+5 =0, then x=-5/4
So x=3/2 or x=-5/4 are the two solutions.
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#2) X^2 -3x=0
In this problem you have to first find the factors:
x(x-3) = 0
If this product is zero, one of those factors must be zero.
If x=0, x=0
if x-3=0, then x=3
So x=0 or x=3 are the two solutions.
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Cheers,
stan H.
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