SOLUTION: The time, in minutes, taken to cook a chicken, C, is linearly related to the weight, in kilograms, of the chicken, k. It takes 40 minutes to cook a 1.4kg chicken and 50 minutes to

Algebra ->  Linear-equations -> SOLUTION: The time, in minutes, taken to cook a chicken, C, is linearly related to the weight, in kilograms, of the chicken, k. It takes 40 minutes to cook a 1.4kg chicken and 50 minutes to       Log On


   



Question 707063: The time, in minutes, taken to cook a chicken, C, is linearly related to the weight, in kilograms, of the chicken, k. It takes 40 minutes to cook a 1.4kg chicken and 50 minutes to cook a 1.8kg chicken.
Find the linear equation relating cooking time, C, with the weight of the chicken, k to find how long it would take to cook a 1.7kg chicken.
how would i solve this equation? as far asi can figure you would go C=C*k-1.7

Answer by nerdybill(7384) About Me  (Show Source):
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The time, in minutes, taken to cook a chicken, C, is linearly related to the weight, in kilograms, of the chicken, k. It takes 40 minutes to cook a 1.4kg chicken and 50 minutes to cook a 1.8kg chicken.
Find the linear equation relating cooking time, C, with the weight of the chicken, k to find how long it would take to cook a 1.7kg chicken.
how would i solve this equation? as far asi can figure you would go C=C*k-1.7
.
The problem gives you two points:
(1.4, 40)
and
(1.8, 50)
.
Determine the equation from the two points.
Slope:
m = (y2-y1)/(x2-x1)
m = (50-40)/(1.8-1.4)
m = (10)/(.4)
m = 25
Now, use the slope (25) and one of the two points, say (1.4, 40) and plug it into the "point-slope" form:
y - y1 = m(x - x1)
y - 40 = 25(x - 1.4)
y - 40 = 25x - 35
y = 25x + 5
.
So, now we can answer:
Find the linear equation relating cooking time, C, with the weight of the chicken, k:
c = 25k + 5
and, to find how long it would take to cook a 1.7kg chicken.
c = 25(1.7) + 5 = 47.5 minutes