SOLUTION: Factor the polynomial 18a^2b^3c-45ab^6c completely

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Question 706845: Factor the polynomial 18a^2b^3c-45ab^6c completely
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
18a%5E2b%5E3c-45ab%5E6c has just two terms: 18a%5E2b%5E3c and 45ab%5E6c
The numeric coefficients have 9 as a common factor:
18=9%2A2 and 45=9%2A5
The variable a appears as a in one term and as a%5E2=a%2Aa in the other,
so a is a factor common to both terms.
The variable b appears as b%5E3 in one term and as b%5E6=b%5E3%2Ab%5E3 in the other,
so b%5E3 is a factor common to both terms.
The variable c appears as c in both terms,
so c is a factor common to both terms.
Taking out common factors,
18a%5E2b%5E3c=9ab%5E3c%282a%29%29 and
-45ab%5E6c=9ab%5E3c%28-5b%5E3%29, so
18a%5E2b%5E3c-45ab%5E6c=9ab%5E3c%282a-5b%5E3%29