SOLUTION: the length of time a customer must wait in line at the post office has approximately a normal distribution with a mean of 5.8 minutes and a standard deviation of 2.6 minutes. what
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Question 706829: the length of time a customer must wait in line at the post office has approximately a normal distribution with a mean of 5.8 minutes and a standard deviation of 2.6 minutes. what is the probability that a customer will wait between 4 and 8 minutes? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the length of time a customer must wait in line at the post office has approximately a normal distribution with a mean of 5.8 minutes and a standard deviation of 2.6 minutes. what is the probability that a customer will wait between 4 and 8 minutes?
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P(4<= x <=8) = P(z(4)<= z <=z(8))
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z(8) = (8-5.8)/2.6 = 0.8462
z(4) = (4-5.8)/2.6 = -0.6923
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Ans: normalcdf(-0.6923,0.8462) = 0.5569
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Cheers,
Stan H.
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