SOLUTION: 1) ( 2 log 9 base 27)- (4 log 8 base 4) 2)log 32 ^-1 base 2

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Question 706716: 1) ( 2 log 9 base 27)- (4 log 8 base 4)
2)log 32 ^-1 base 2
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1) ( 2 log 9 base 27)- (4 log 8 base 4)
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2*log27(9) - 4log4(8)
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= 2[log3(9)/log3(27)] - 4[log2(8)/log2(4)]
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= 2[2/3] - 4[3/2]
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= (4/3) - 6
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= -4 2/3
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2)log 32 ^-1 base 2
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log2[32^-1]
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= log2(2^-5)
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= -5
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Cheers,
Stan H.
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