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Question 706709: Write an equation of the line that is perpendicular to 5x + 20y = 10 and passes through the point (8, 3)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Write an equation of the line that is perpendicular to 5x + 20y = 10 and passes through the point (8, 3)
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Find the slope of the given line:
5x + 20y = 10
y = (-1/4)x + (1/2)
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slope = -1/4
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Therefore slope of the perpendicular line must be 4
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Form: y = mx + b
You have y = 3 when x = 8 , and m = 4
Solve for "b":
3 = 4*8 + b
b = 29
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Equation:
y = 4x + 29
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Cheers,
Stan H.
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