SOLUTION: Twice a number decreased by 3 is less than 12. One more than three times the same number is greater than 20. Find the number. a) 5 b) 6 c) 7 d) 8 e) 9

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Twice a number decreased by 3 is less than 12. One more than three times the same number is greater than 20. Find the number. a) 5 b) 6 c) 7 d) 8 e) 9      Log On


   

Question 706706: Twice a number decreased by 3 is less than 12. One more than three times the same number is greater than 20. Find the number.
a) 5
b) 6
c) 7
d) 8
e) 9
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Twice a number decreased by 3 is less than 12. One more than three times the same number is greater than 20. Find the number.
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Let the number be "x":
2x-3 < 12
3x+1 > 20
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Modify each inequality
x < 15/2 = 7.5
x > 19/3 > 6.333..
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Ans: 7
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Cheers,
Stan H.
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a) 5
b) 6
c) 7
d) 8
e) 9