SOLUTION: dyke is 27 year older than his daughter In ten years he will be twice as old as his daughter how old are they now

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Question 706438:
dyke is 27 year older than his daughter In ten years he will be twice as old as his daughter how old are they now
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
X=Y+27
X+10=2(Y+10)SUBTRACT.
---------------------------
-10=Y-2Y+27-20
-10=-Y+7
-Y=-10-7
Y=17 AGE OF THE DAUGHTER NOW.
X=17+27=44 AGE OF DAD NOW.
PROOF:
44+10=2(17+10)
54=2*27
54=54