SOLUTION: HELP!!! Find the general equation of each line; that is write the equation in the form Ax+By+C Containing the points (1,3) and (-1,2). Thank you for your help!

Algebra ->  Linear-equations -> SOLUTION: HELP!!! Find the general equation of each line; that is write the equation in the form Ax+By+C Containing the points (1,3) and (-1,2). Thank you for your help!      Log On


   

Question 706346: HELP!!! Find the general equation of each line; that is write the equation in the form Ax+By+C Containing the points (1,3) and (-1,2). Thank you for your help!
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (1, 3) and (x2, y2) = (-1, 2).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%282-3%29%2F%28-1-1%29+=+0.5.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 0.5%2A1+%2Bb+=+2.5. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=3-0.5%2A1+=+2.5.

y=(0.5)x + (2.5)

Your graph:





here you have y=0.5x+%2B+2.5 which is slope-intercept form and the equation in the form Ax%2BBy%2BC=0 is -0.5x%2By-2.5=0