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Question 706313: Hi. I've solved for t but still can't figure out how to solve for the questions. Thank you for your help.
Here is the problem:
What is the slope of the line x=-3t+10 and y=4t+2.
(a) m=
(b) Where does the line cross the x-axis? (______,0)
(c) Where does the line cross the y-axis? (0,______)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Here is the problem:
Comment: Didn't notice the problem was parametric.
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What is the slope of the line x=-3t+10 and y=4t+2.
3t = -x+10
t = (-x+10)/3
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4t = y-2
t = (y-2)/4
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Equate the "t" values:
(-x+10)/3 = (y-2)/4
Cross-multiply::::
3(y-2) = 4(-x+10)
3y-6 = -4x + 40
3y = -4x + 46
y = (-4/3)x + (46/3)
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(a) m= -4/3
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(b) Where does the line cross the x-axis? (______,0)
y = (-4/3)x + (46/3)
(-4x+46)/3 = 0
-4x = -46
x = 46/4
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(c) Where does the line cross the y-axis? (0,______)
y = (-4/3)x + (46/3)
y = (46/3)
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Cheers,
Stan H.
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