SOLUTION: 5(2x+1)+4<8x+6

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Question 70628: 5(2x+1)+4<8x+6
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
5%282x%2B1%29%2B4%3C8x%2B6
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Operate on this just as you would on an equation. For the first step, you can multiply
out the left side to get:
.
10x+%2B+5+%2B+4+%3C+8x+%2B+6
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Combine the +5 and the +4 on the left side. The inequality becomes:
.
10x+%2B+9+%3C+8x+%2B+6
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Eliminate the +9 on the left side by adding -9 to both sides:
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10x+%3C+8x+%2B6+-9
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And add the +6 and -9 on the right side:
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10x+%3C+8x+-+3
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Get rid of the 8x on the right side by adding -8x to both sides. The inequality simplifies to:
.
2x+%3C+-3
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Dividing both sides by 2 results in:
.
x+%3C+%28-3%2F2%29
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This tells you that x can be anywhere on the number line below the value -3%2F2.
But x cannot equal %28-3%2F2%29and it cannot be any value to the right of %28-3%2F2%29
on the number line.
.
It doesn't happen in this problem, but remember this rule: if you multiply or divide an
inequality by a negative number you must change the inequality sign to the opposite
direction.
.
Hope this helps you see how to work with inequalities.