SOLUTION: one side of a trianglular sail is 10 feet longer than the shortest side. the other side is twice as long as the shortest side. find each side if the perimeter is 42 feet.
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Question 706254: one side of a trianglular sail is 10 feet longer than the shortest side. the other side is twice as long as the shortest side. find each side if the perimeter is 42 feet. Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! P=A+B+C
LET X BE THE SHORTER SIDE (A).
LET X+10 BE THE SECOND SIDE (B).
LET 2X BE THE THIRD SIDE (C).
42=X+X+10+2X
42-10=4X
32=4X
X=32/4
X=8 ANS. FOR THE SHORTEST SIDE (A).
8+10=18 ANS. FOR THE SECOND SIDE (B).
2*8=16 ANS. FOR THE THIRD SIDE (C).
PROOF:
42=8+18+16
42=42
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