SOLUTION: how many gallons of 60% alcohol solution must be mixed with 60 gallons of 14% solution to obtain a solution that is 40% alcohol?

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Question 706248: how many gallons of 60% alcohol solution must be mixed with 60 gallons of 14% solution to obtain a solution that is 40% alcohol?
Answer by josgarithmetic(39614) About Me  (Show Source):
You can put this solution on YOUR website!
Let g = amount of gallons of the 60% alcohol to add.
40% is target concentration.

%28g60%2B60%2A14%29%2F%28g%2B60%29=40,(do not become confused about what the "60"s are counting while setting the initial equation.)

60g%2B60%2A14=40%28g%2B60%29
3g+3*14=2(g+60)
3g+3*14=2g+120
g+42=120
g=120-42=7
g=7 gallons of the 60% alcohol