SOLUTION: What are the points of discontinuity? y= (x+2)(x+7)/(x^2-5x-14)

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Question 706215: What are the points of discontinuity?
y= (x+2)(x+7)/(x^2-5x-14)
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Discontinuity could happen for x at which the denominator is zero.
x%5E2-5x-14=%28x-7%29%28x%2B2%29=0
x=7 or x=-2