Question 705740: Finding the real solutions to the equation:
Please help me solve this: 5x^2/3-24x^1/3-5=0
I got to the second part of this answer which is 125...but I cant figure out the fraction part. The answer should look something like this: -number/number,125
Found 2 solutions by Alan3354, lynnlo:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Finding the real solutions to the equation:
Please help me solve this: 5x^2/3-24x^1/3-5=0
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Sub u for x^(1/3)
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5u^2 - 24u - 5 = 0
(5u + 1)*(u - 5) = 0
u = 5
x^(1/3) = 5
x = 125
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u = -1/5
x = -1/125
Answer by lynnlo(4176)  (Show Source):
You can put this solution on YOUR website! 5x^2/3-24x^1/3-5=0
5x^2/3-8x^1/1-5=0
5x^2/3-8x^1-5=0
5x^2-8x-5=0
x=12+square root219/5 or12-square root219/5
x~5.3597,,,,,,,,,,,,-0.5597
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