SOLUTION: I have a question to simplify the square root of 216. I think the answer is 6 times the square root of 6, but I'm not sure...

Algebra ->  Radicals -> SOLUTION: I have a question to simplify the square root of 216. I think the answer is 6 times the square root of 6, but I'm not sure...       Log On


   



Question 705440: I have a question to simplify the square root of 216. I think the answer is 6 times the square root of 6, but I'm not sure...


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You are 100% correct

For more help/practice with simplifying square roots, check out this solver: http://www.algebra.com/algebra/homework/Radicals/simplifying-square-roots.solver

Solved by pluggable solver: Simplifying Square Roots (whole numbers only)
sqrt%28216%29 Start with the given expression


The goal of simplifying expressions with square roots is to factor the radicand into a product of two numbers. One of these two numbers must be a perfect square. When you take the square root of this perfect square, you will get a rational number.

So let's list the factors of 216

Factors:

1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 27, 36, 54, 72, 108, 216



Notice how 36 is the largest perfect square, so lets factor 216 into 36*6





sqrt%2836%2A6%29 Factor 216 into 36*6



sqrt%2836%29%2Asqrt%286%29 Break up the square roots using the identity sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29



6%2Asqrt%286%29 Take the square root of the perfect square 36 to get 6



So the expression sqrt%28216%29 simplifies to 6%2Asqrt%286%29



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Check:

Notice if we evaluate the square root of 216 with a calculator we get


sqrt%28216%29=14.6969384566991


and if we evaluate 6%2Asqrt%286%29 we get


6%2Asqrt%286%29=14.6969384566991


This shows that sqrt%28216%29=6%2Asqrt%286%29. So this verifies our answer



For more help/practice with simplifying square roots, check out this solver: http://www.algebra.com/algebra/homework/Radicals/simplifying-square-roots.solver