SOLUTION: Find the GCF of each product. (6y^2 - 3y)(y + 7) I need a little help with this one. Thank you.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the GCF of each product. (6y^2 - 3y)(y + 7) I need a little help with this one. Thank you.       Log On


   

Question 70541This question is from textbook Beginning Algebra
: Find the GCF of each product. (6y^2 - 3y)(y + 7)
I need a little help with this one. Thank you. This question is from textbook Beginning Algebra

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Find the GCF of each product. (6y^2 - 3y)(y + 7)
%286y%5E2-3y%29%2A%28y%2B7%29
3y%28y-1%29%2A%28y%2B7%29
The GCF is 3y
If you don't understand it that way, FOIL the parentheses and take out the GCF:
6y%5E2%28y%2B7%29-3y%28y%2B7%29
6y%5E3%2B42y%5E2-3y%5E2-21y
6y%5E3%2B39y%5E2-21y
3y%282y%5E2%29%2B3y%2813y%29%2B3y%28-7%29
3y%282y%5E2%2B13y-7%29
It's a little more work, but....
The GCF is still 3y
Happy Calculating!!!