SOLUTION: Find all real zeros of the function g(x)=x^3+4x^2-x-4

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Question 705310: Find all real zeros of the function g(x)=x^3+4x^2-x-4
Answer by nerdybill(7384) About Me  (Show Source):
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Find all real zeros of the function g(x)=x^3+4x^2-x-4
.
Possible zeros:
4/1 = +-[1,2,4]
.
Using synthetic division try 1:
1 | 1 4 -1 -4
1 5 4
---------------
1 5 4 0
since we have a zero remainder, we know 1 is a root.
So, it factors to:
(x-1)(x^2+5x+4)
Now, we can factor (using normal methods):
(x-1)(x+4)(x+1)
Real zeros are at
x={1, -4, -1}