Question 705185: Factor 24b^2-150
Answer by lenny460(1073)   (Show Source):
You can put this solution on YOUR website! Factor 24b^2-150
Divide each term by 6
24b^2 / 6 = 4b^2
-150 / 6 = -25
Therefore we now have:
6(4b^2 - 25)
4b^2 - 25 is a perfect square.
We factor the difference of two squares:
4b^2 - 25 = (2b - 5)(2b + 5)
Therefore the answer is:
6(2b - 5)(2b + 5)
Lennox Obuong
Algebra Tutor
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